log2x=log2/\3+log2/\5 lg2x-lgx-2=0

log2 x -log2 3=log 2 (2x-5) I'm assuming everthing in the above question is to log of base 2.log2 x -log2 3=log2 (2x-5) Apply logarithm law: log a — log b=log (a/b) log2 (x/3)=log2 (2x-5) Remove the log function from both sides of the equation.x/3=2x-5