1+cosx/sin²x/ (1+(1+cosx) /sinx) ²) Очень срочно! Помогите пожалуйста!

1+cosx/sin^2x/ (1+(1+cosx) /sinx) ^2)=2cos^2 (x/2) /4sin^2 (x/2) cos^2 (x/2) / (1+2 (1+cosx/sinx)+(1+cosx/sinx) ^2)=1/2sin^2 (x/2) / (1+2 (1+cosx) /sinx)+(1+2cosx+cos^2x) /sin^2x)=1/2sin^2 (x/2) / (1+2 (1+cosx) /sinx)+(1+cosx) /sin^2x)+(cosx+cos^2x) /sin^2x)=1/2sin^2 (x/2) / (1+2 (2cos^2 (x/2) /4sin^ (x/2) cos^2 (x/2)+(2cos^2 (x/2) /4sin^2 (x/2) cos^2 (x/2)+(cosx (1+cosx) /sin^2x)=1/2sin^2 (x/2) / (1+(2cos (x/2) /sin (x/2)+(1/sin^2 (x/2)+(cosx/2sin^2 (x/2)=1/2sin^2 (x/2) / (2sin^2 (x/2)+4cos (x/2) sin (x/2)+2+cosx) /2sin^2x)=1/ (2sin^2 (x/2)+2sin2x+2+cosx)=1/ (1-cosx+2sinx+cosx)=1/ (1+2sinx) Ответ: 1/ (1+2sinx)