Упростите выражение 1+sin2a+cos2a?

=cos²α+sin²α+2sinαcosα+cos²α-sin²α=2c0s²α+2sinαc0sα=2cosα (cosα+sinα)=2cosα (sin (π/2-α)+sinα)=2cosα·2sin (π/2-α+α) /2·cos (π/2-α-α) /2=4cosα·sinπ/4·cos (π/4-α)=4cosα·√2/2·cos (π/4-α)=2√2cosα·cos (π/4-α)