1) f (x)=\sqrt (6x-7) при x (0)=3 2) f (x)=cos^4x при x

1) f ' (x)=(√ (6*x — 7) '=(6*x — 7) '/ (2*√ (6*x — 7)=6 / (2*√ (6*x — 7)=3 / √ (6*x — 7) При Х0=3 f ' (3)=3 / √ (6*3 — 7)=3 / √ 11. '2) f ' (x)=(cos⁴x) '=4*cos³x*(cos x) '=4*cos³x*(- sin x)=-4*cos³x*sin xПри Х0=π/4 f ' (π/4)=-4*cos³ (π/4)*sin π/4=-4*(1 / √ 2) ³*(1/ √ 2)=-1